Here is the Final UPCAT Sample Quiz in the Science Subtest. If you find any errors in the quiz, please dont hesitate to let us know about it through the comments section. Moreover, if you have a better solution set or explanation that is provided in the solution sets, please dont hesitate to share it too.
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Physics Quiz
Question 1 
A  35 meters 
B  75 meters 
C  20 meters 
D  50 meters 
Question 2 
A  Reflection 
B  Theta 
C  Periods 
D  Cycles 
Question 3 
A  93.33 m/s 
B  75 m/s 
C  36.67 m/s 
D  2 m/s 
Question 4 
A  opposite 
B  the same 
C  at an angle with each other. 
D  perpendicular 
Question 5 
A  500 N 
B  400 N 
C  300 N 
D  600 N 
Question 6 
A  2.5 m/s 
B  2.14 m/s 
C  25 m/s 
D  15 m/s 
Question 7 
A  The sum of the voltage rating divided by the resistance of the load. 
B  The voltage rating of each battery. 
C  The sum of their voltage ratings. 
D  The voltage rating divided by the resistance of the load. 
Question 8 
A  1567.13 W 
B  1718.75 W 
C  2341.12 W 
D  5500 W 
Question 9 
A  kg/L 
B  kg∙m/s 
C  kg∙m^2 
D  kg∙m/s^2 
Question 10 
A  F=200/sin 20^{o} 
B  F=200/cos 20^{o} 
C  F = (200)(cos 20^{o}) 
D  F = (200)(sin 20^{o}) 
Question 11 
A  A ball thrown upwards 
B  A cart moving downhill on a mountain slope 
C  A car running along a curve 
D  A book on the table 
Question 12 
A  20 N 
B  25 N 
C  29 N 
D  35 N 
Question 13 
A  A train slowing down before reaching the station. 
B  A ball falling from an airplane. 
C  A man on a bus being “pushed” backward when the bus starts moving. 
D  A tanker in full speed turning its engine in reverse an hour before reaching the port. 
Question 14 
A  0 N 
B  4 N 
C  10 N 
D  7 N 
Question 15 
A  Kinetic energy depends upon the position of the object. 
B  Free falling objects have increasing kinetic energy. 
C  Kinetic energy is always positive. 
D  If two objects have the same mass then the one that moves faster has the greater kinetic energy. 
Question 16 
A  It is quartered. 
B  It is quadrupled. 
C  It is halved. 
D  It is doubled. 
Question 17 
A  A 
B  C 
C  D 
D  B 
Question 18 
A  1.1 Km 
B  0.9 Km 
C  0.7 Km 
D  1.3 Km 
Question 19 
A  They bounce sideways. 
B  They bounce back with the same speed and distance. 
C  Could not be determined. 
D  They stick together. 
Question 20 
A  stops, bounces off 
B  bounces off, changes speed 
C  bounces off, changes direction 
D  passes through, bounces off 
Question 21 
A  10 Joules 
B  1 Joule 
C  100 Joules 
D  1000 Joules 
Question 22 
A  7 m/s2 
B  8.25 m/s2 
C  5 m/s2 
D  9 m/s2 
Question 23 
A  Joule 
B  Watt 
C  \(N\centerdot m\) 
D  \(\frac{kg\centerdot {{m}^{2}}}{{{s}^{2}}}\) 
Question 24 
A  instantaneous speed 
B  ordinary speed 
C  average speed 
D  uniform speed 
Question 25 
A  Wavelength 
B  Speed 
C  Acceleration 
D  Frequency 
Question 26 
A  Energy 
B  Wavelength 
C  Frequency 
D  penetrability 
Question 27 
A  Has potential energy 
B  Not changing direction 
C  Not changing speed 
D  Not moving 
Question 28 
A  Car A went on reverse at t = 6 secs and is moving at constant velocity at t = 3 secs until it accelerated at t = 4 secs. 
B  Car A went on reverse at t = 6 secs and stopped moving at t = 3 secs and resumed motion at t = 4 secs. 
C  Car A stopped moving at t = 6 secs and is moving at constant velocity at t = 3 secs until it accelerated at t = 4 secs. 
D  Car A decelerated at t = 6 secs and is moving at constant velocity at t = 3 secs until it accelerated at t = 4 secs. 
Question 29 
A  enlarged 
B  the same

C  virtual 
D  reduced 
Question 30 
A  Mechanics 
B  Static 
C  kinematics 
D  kinetics 
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 UPCAT Sample Test: Basic Math
 UPCAT Sample Questions: Biology
 UPCAT Sample Exam: Chemistry
 UPCAT Review Questions: Algebra
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Number 13
Mali yung computation,
Vf=Vi+at
120=0+a(5)
a=120/5
a=24m/s
so kung force hinahanap F=ma
F=(800kg)(24m/s)
F=19200 N
wala yung sagot sa choices
22/30 🙁 practice pa moreeeee!bring it on!
Correction: L1 = 80cm not L2. L2 = 80cm x 500N / 1500N, L2 = 26.67cm (means that 1500N is 26.67cm from the fulcrum).
Haha tnx d2 mas nging broad yung mind ko sa lalabas sa UPCAT <3
Help me po,Im taking UPCAT this August,give me somd tips,hints sa mga pweding lumabas this year’s UPCAT,09273336362,number ko,text or call me nalang f u can help me. Thanks in advance
Help me po,Im taking UPCAT this August,give me somd tips,hints sa mga pweding lumabas this year’s UPCAT
kailan po yung UPCAT for batch 20122013?
The UPCAT for AY 20122013 freshmen was held in August 2011. The UPCAT for AY 20132014 freshmen (those who want to become UP Freshies in June 2013) will be administered in August 2012.
i need to practice more :)) i only got 12 :))
At least you still have time to practice. Incoming 4th year HS student? 🙂
@Arvi, Is that how it is? But I thought the heavier person should be much closed to the center so that the seesaw would balance. Since the distance of the lighter person is 20cm from the center, shouldn’t the distance of the heavier person be smaller?
Pls reread. It’s 20cm from the left side. So it’s 80cm from the center given the length of seesaw is 2m (200cm), half of it being 1m (100cm). I agree with Arvi.
Hope I helped! 🙂
kelan po deadline ng application form ng ustet
Hi!
I’m Arvi from UP Diliman, Eng’g Batch ’03.
I’d like to correct the solution to question no. 25. Following your line of explanation, L1/ F1 = L2/ F2, we can’t simply express the moment arms (L1 & L2) proportional to the forces (F1 & F2) in this manner. In Physics, this is governed by statics, wherein the summation of forces and moments must equal to zero at equilibrium (to prevent the seesaw from moving or changing its horizontal position.) Hence, the correct proportion should have been L1/F2 = L2/F1 or L1xF1 (moment of F1) = L2 x F2 (moment of F2) using the fulcrum (center of seesaw) as our reference for the moments. Wherein L1 & L2 are the moment arms, F1 & F2 are the forces or weights of the bodies. Once you get L2, subtract it from 1m or 100cm to get the answer.
Moreover, using the center of the seesaw as our point to get the summation of moments, L1 would be 80cm from the fulcrum. F1 is 500N. The moment of force would be F1 x L1 (500N x 80cm = 40000 N.cm, counterclockwise) This moment must be equal to the moment of force, F2 = 1500N in order to maintain equilibrium (F2 will cause a moment in the clockwise direction). The position, x, from the fulcrum multiplied by F2 must be equal to 40,000 N.cm. Solving for x; 40000 = 1500x, x = 26.67cm. Hence, the answer must be 100 – x = 100 – 26.67 = 73.33 from the right side of the seesaw.
Therefore, the answer in not in the given choices. Just my two cents.
ang galing galing nman..
i agree on your equation ARVI, which is L1/F2 = L2/F1, but with respect to the given length of the seesaw which is 2meters (200cm), the distance from the fulcrum on the left side is 180cm (L1=180cm). F1 and F2 are the weight of the boy and the man (F1=500N, F2=1,500N). Thus. L2= (L1*F1)/F2,
L2=(180cm*500N) / 1,500N
L2=90,000cmN / 1,500N
L2=60cm
Hence, the answer remains to be 60cm (which is included on the choices) however the explanation should be edited.
Fulcrum is in the middle of the seesaw, therefore L2=80cm not 180cm.