Here is the Final UPCAT Sample Quiz in the Science Subtest. If you find any errors in the quiz, please dont hesitate to let us know about it through the comments section. Moreover, if you have a better solution set or explanation that is provided in the solution sets, please dont hesitate to share it too.
You might want to read more about the UPCAT after taking the quiz. Here is a compilation of all our UPCAT tips and strategies organized into one post: UPCAT: Your Ultimate Guide. You might also want to check out our 101 UPCAT Tips on the fanpage. Finally, you might want to join the discussion and be updated on college entrance exam news and tips on our Fanpage or be a part of the 2011 UPCAT Review group where students like you help each other review for the UPCAT.
Physics Quiz
Question 1 
A  4 N 
B  1 N 
C  3 N 
D  2 N 
Given : m = 2 kg a = 0.5 m/s^{2}
F = mass x acceleration
F = 2 kg x 0.5 m/s^{2} = 1 kg m/s^{2} = 1 N
Question 2 
A  It is accelerating towards the center. 
B  It is not accelerating. 
C  None of the above. 
D  It is accelerating tangent to the circle. 
Question 3 
A  t = 0 secs to t = 2 secs. 
B  t = 2 secs to t = 4 secs. 
C  t = 4 secs to t = 6 secs. 
D  t = 6 secs to t = 8 secs. 
Question 4 
A  Because the fish moves too fast. 
B  Because light travels at a different speed on water. 
C  Because light bounces off the ocean floor. 
D  This phenomenon is not true. 
Question 5 
A  1.50 kJ 
B  2.25 kJ 
C  1.75 kJ 
D  2.00 kJ 
m = 500 kg v = 3.0 m/s
KE = 1/2 (500kg) (9m^2/s^2) = 2.25 KJ
Question 6 
A  2000 N 
B  20000 N 
C  20000 N 
D  2000 N 
Question 7 
A  path and direction 
B  magnitude and unit 
C  mass and direction 
D  magnitude and direction 
Question 8 
A  Amplitude 
B  Frequency 
C  Wave length 
D  Pitch 
Question 9 
A  They travel with the same speed in the absence of vacuum. 
B  They are produced by moving charges. 
C  They require a medium for transmission 
D  They are transverse waves. 
Question 10 
A  A train slowing down before reaching the station. 
B  A ball falling from an airplane. 
C  A tanker in full speed turning its engine in reverse an hour before reaching the port. 
D  A man on a bus being “pushed” backward when the bus starts moving. 
Question 11 
A  Carrie is exerting force on the block. 
B  The block is exerting force on Carrie. 
C  Neither a and b. 
D  Both a and b. 
Question 12 
A  Force 
B  Impulse 
C  Acceleration 
D  Momentum 
Question 13 
A  4.5 KN 
B  3.0 KN 
C  2.5 KN 
D  1.5 KN 
force = [(100 kg)(900m^2/s^2)/60m = 1500kgm/s^2
= 1500 N = 1.5 kN
Question 14 
A  passes through, bounces off 
B  stops, bounces off 
C  bounces off, changes speed 
D  bounces off, changes direction 
Question 15 
A  60 cm 
B  40 cm 
C  80 cm 
D  20 cm 
\(\frac{L_{1}}{F_{1}}=\frac{L_{2}}{F_{2}}\)
\(L_{2}=\frac{L_{1}F_{2}}{F_{1}}= \frac{20cmX1500N}{500N}= 60cm\)
Question 16 
A  Tripled 
B  Halved 
C  Doubled 
D  Quartered 
Question 17 
A  4 N 
B  7 N 
C  10 N 
D  0 N 
Question 18 
A  the same 
B  twice 
C  half 
D  onethird 
Question 19 
A  kg∙m^2 
B  kg/L 
C  kg∙m/s 
D  kg∙m/s^2 
Question 20 
A  uniform circular motion 
B  rectilinear motion 
C  horizontal motion 
D  projectile motion 
Question 21 
A  the same

B  enlarged 
C  virtual 
D  reduced 
Question 22 
A  The mirror was concave. 
B  The mirror has nothing to do with it. 
C  The mirror was taller. 
D  The mirror was convex. 
Question 23 
A  increases, increases 
B  increases, decreases 
C  decreases, stays the same 
D  decreases, decreases 
Question 24 
A  A book on the table 
B  A car running along a curve 
C  A cart moving downhill on a mountain slope 
D  A ball thrown upwards 
Question 25 
A  D 
B  B 
C  A 
D  C 
Question 26 
A  V_{f} = V_{i}^{2} + 2aΔt 
B  V_{f} = V_{i} – aΔt 
C  V_{f} = 2V_{i} + aΔt 
D  V_{f} = V_{i} + aΔt 
Question 27 
A  average speed 
B  ordinary speed 
C  uniform speed 
D  instantaneous speed 
Question 28 
A  1.1 Km 
B  0.9 Km 
C  0.7 Km 
D  1.3 Km 
Question 29 
A  Momentum is a force. 
B  An object has a bigger mass then it will have a larger momentum than a smaller object. 
C  Momentum is scalar. 
D  Momentum only applies to moving objects. 
Question 30 
A  infrasonic 
B  supersonic 
C  mega sonic 
D  ultrasonic 
Related posts:
 UPCAT Sample Questions: General Science
 UPCAT Sample Test: Basic Math
 UPCAT Sample Questions: Biology
 UPCAT Sample Exam: Chemistry
 UPCAT Review Questions: Algebra
 UPCAT Review Questions: Sample Trigonometry / Geometry Quiz
 UPCAT Review Questions: Sample Parts of Speech/General Grammar Rules Quiz
 UPCAT Sample Questions: Syntax and Mechanics
 UPCAT Reviewer / Sample Quiz: Diction and Vocabulary
 UPCAT Sample Quiz: Advanced Algebra and Statistics
 UPCAT Mock Exam: Reading Comprehension
Number 13
Mali yung computation,
Vf=Vi+at
120=0+a(5)
a=120/5
a=24m/s
so kung force hinahanap F=ma
F=(800kg)(24m/s)
F=19200 N
wala yung sagot sa choices
22/30 🙁 practice pa moreeeee!bring it on!
Correction: L1 = 80cm not L2. L2 = 80cm x 500N / 1500N, L2 = 26.67cm (means that 1500N is 26.67cm from the fulcrum).
Haha tnx d2 mas nging broad yung mind ko sa lalabas sa UPCAT <3
Help me po,Im taking UPCAT this August,give me somd tips,hints sa mga pweding lumabas this year’s UPCAT,09273336362,number ko,text or call me nalang f u can help me. Thanks in advance
Help me po,Im taking UPCAT this August,give me somd tips,hints sa mga pweding lumabas this year’s UPCAT
kailan po yung UPCAT for batch 20122013?
The UPCAT for AY 20122013 freshmen was held in August 2011. The UPCAT for AY 20132014 freshmen (those who want to become UP Freshies in June 2013) will be administered in August 2012.
i need to practice more :)) i only got 12 :))
At least you still have time to practice. Incoming 4th year HS student? 🙂
@Arvi, Is that how it is? But I thought the heavier person should be much closed to the center so that the seesaw would balance. Since the distance of the lighter person is 20cm from the center, shouldn’t the distance of the heavier person be smaller?
Pls reread. It’s 20cm from the left side. So it’s 80cm from the center given the length of seesaw is 2m (200cm), half of it being 1m (100cm). I agree with Arvi.
Hope I helped! 🙂
kelan po deadline ng application form ng ustet
Hi!
I’m Arvi from UP Diliman, Eng’g Batch ’03.
I’d like to correct the solution to question no. 25. Following your line of explanation, L1/ F1 = L2/ F2, we can’t simply express the moment arms (L1 & L2) proportional to the forces (F1 & F2) in this manner. In Physics, this is governed by statics, wherein the summation of forces and moments must equal to zero at equilibrium (to prevent the seesaw from moving or changing its horizontal position.) Hence, the correct proportion should have been L1/F2 = L2/F1 or L1xF1 (moment of F1) = L2 x F2 (moment of F2) using the fulcrum (center of seesaw) as our reference for the moments. Wherein L1 & L2 are the moment arms, F1 & F2 are the forces or weights of the bodies. Once you get L2, subtract it from 1m or 100cm to get the answer.
Moreover, using the center of the seesaw as our point to get the summation of moments, L1 would be 80cm from the fulcrum. F1 is 500N. The moment of force would be F1 x L1 (500N x 80cm = 40000 N.cm, counterclockwise) This moment must be equal to the moment of force, F2 = 1500N in order to maintain equilibrium (F2 will cause a moment in the clockwise direction). The position, x, from the fulcrum multiplied by F2 must be equal to 40,000 N.cm. Solving for x; 40000 = 1500x, x = 26.67cm. Hence, the answer must be 100 – x = 100 – 26.67 = 73.33 from the right side of the seesaw.
Therefore, the answer in not in the given choices. Just my two cents.
ang galing galing nman..
i agree on your equation ARVI, which is L1/F2 = L2/F1, but with respect to the given length of the seesaw which is 2meters (200cm), the distance from the fulcrum on the left side is 180cm (L1=180cm). F1 and F2 are the weight of the boy and the man (F1=500N, F2=1,500N). Thus. L2= (L1*F1)/F2,
L2=(180cm*500N) / 1,500N
L2=90,000cmN / 1,500N
L2=60cm
Hence, the answer remains to be 60cm (which is included on the choices) however the explanation should be edited.
Fulcrum is in the middle of the seesaw, therefore L2=80cm not 180cm.