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UPCAT Mock Test: Physics

UPCAT Sample Quiz

Here is the Final UPCAT Sample Quiz in the Science Subtest.  Remember that we do not have any timers for the quizzes so you may want to time yourself here.  If you find any errors in the quiz, please dont hesitate to let us know about it through the comments section.  Moreover, if you have a better solution set or explanation that is provided in the solution sets, please dont hesitate to share it too.


You might want to read more about the UPCAT after taking the quiz.   Here is a compilation of all our UPCAT tips and strategies organized into one post:  UPCAT: Your Ultimate Guide. You might also want to check out our 101 UPCAT Tips on the fanpage.  Finally, you might want to join the discussion and be updated on college entrance exam news and tips on our Fanpage or be a part of the 2011 UPCAT Review group where students like you help each other review for the UPCAT.


Physics Quiz

Directions: For each statement or question, choose the letter of the word or expression that, of those given, best completes or answers the question. ► Calculators of any kind are not permitted. All numbers used are real numbers.
Congratulations - you have completed Physics Quiz. You scored %%SCORE%% out of %%TOTAL%%. Your performance has been rated as %%RATING%%
Your answers are highlighted below.

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7 thoughts on “UPCAT Mock Test: Physics

    • The UPCAT for AY 2012-2013 freshmen was held in August 2011. The UPCAT for AY 2013-2014 freshmen (those who want to become UP Freshies in June 2013) will be administered in August 2012.

  1. @Arvi, Is that how it is? But I thought the heavier person should be much closed to the center so that the seesaw would balance. Since the distance of the lighter person is 20cm from the center, shouldn’t the distance of the heavier person be smaller?

  2. Hi!

    I’m Arvi from UP Diliman, Eng’g Batch ’03.

    I’d like to correct the solution to question no. 25. Following your line of explanation, L1/ F1 = L2/ F2, we can’t simply express the moment arms (L1 & L2) proportional to the forces (F1 & F2) in this manner. In Physics, this is governed by statics, wherein the summation of forces and moments must equal to zero at equilibrium (to prevent the see-saw from moving or changing its horizontal position.) Hence, the correct proportion should have been L1/F2 = L2/F1 or L1xF1 (moment of F1) = L2 x F2 (moment of F2) using the fulcrum (center of see-saw) as our reference for the moments. Wherein L1 & L2 are the moment arms, F1 & F2 are the forces or weights of the bodies. Once you get L2, subtract it from 1m or 100cm to get the answer.

    Moreover, using the center of the see-saw as our point to get the summation of moments, L1 would be 80cm from the fulcrum. F1 is 500N. The moment of force would be F1 x L1 (500N x 80cm = 40000, counterclockwise) This moment must be equal to the moment of force, F2 = 1500N in order to maintain equilibrium (F2 will cause a moment in the clockwise direction). The position, x, from the fulcrum multiplied by F2 must be equal to 40,000 Solving for x; 40000 = 1500x, x = 26.67cm. Hence, the answer must be 100 – x = 100 – 26.67 = 73.33 from the right side of the see-saw.

    Therefore, the answer in not in the given choices. Just my two cents.

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